Find the variance for the given data. Round your answer to one more decimal place than the original data. 4,11,11, 2, and 8.

The variance of any given set of data containing n values
can be calculated as:

V = [(x1 - x)^2 + (x2 - x)^2 + (x3 -
x)^2 + ...  (xn -
x)^2]/n

Where:

x, x2, x3 ...
xn represent the n values, and

x  = mean of n values = (x1
+ x2 + x3 + ... +xn)/n

From the given values we calculate
the mean x as:

x = (4 + 11 + 11 + 2 + 8)/5 = 36/5 =
7.2

And

(x1 - x)^2 = (4 -
7.2)^2 = 10.24

(x2 - x)^2 = (11 - 7.2)^2 =
14.44

(x3 - x)^2 = (11 - 7.2)^2 =
14.44

(x4 - x)^2 = (2 - 7.2)^2 =
27.04

(x5 - x)^2 = (8 - 7.2)^2 =
0.64

And

V = [(x1 - x)^2 + (x2
- x)^2 + (x3 - x)^2 + (x4 - x)^2 + (x5 - x)^2]/5

= 10.24 +
14.44 +143.44 + 27.04 + 0.64)/5

=
66.8

= 13.36

Rounding this off
to 1 decimal place we get
13.4

Answer:

Variance =
13.4