To calculate the indefinite integral, we'll use the
substitution method.
We'll note y =
f(x)
We'll calculate Integral of f(x) = y = cos x / (sin
x)^3.
We notice that if we'll differentiate sin x, we'll
get cos x.
So, we'll note sin x =
t
(sin x)'dx = dt
(cos x)dx =
dt
We'll re-write the integral in the variable
t:
Int (cos x)dx / (sin x)^3 = Int dt /
t^3
Int dt / t^3 = Int
[t^(-3)]dt
Int [t^(-3)]dt = t^(-3+1) / (-3+1) +
C
Int [t^(-3)]dt = t^(-2)/-2 +
C
Int [t^(-3)]dt = -1 / 2t^2 +
C
But sin x =
t.
Int (cos x)dx / (sin x)^3 = -1 / 2(sin
x)^2 + C, where C is a family of constants.
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