We'll write the equation of the line in the standard
form:
y = mx + n, where m is the slope and n is y
intercept.
We know, from enunciation, that the line has the
slope m= 1/2. We'll substitute the value of the slope in the equation of the
line.
y = x/2 + n
The point
(4, -2) is located on the line if and only if it's coordinates verify the equation of
the line:
-2 = 4/2 + n
-2 = 2
+ n
We'll subtract 2 both sides and we'll apply the
symmetric property:
n = -2 -
2
n = -4
The equation of the
line is:
y = x/2 - 4
The
point (m, 4) belongs to the same line if and only if it's coordinates belong to the
line.
4 = m/2 - 4
We'll add 4
both sides:
m/2 = 8
m =
8*2
m =
16
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