We could write 15 = 15*1 = 15*log
10
log x^2 = log 10 + 15*log
10
We'll factorize:
log x^2 =
log 10*(1+15)
log x^2 = 16*log
10
We'll use the power property of
logarithms:
log x^2 = log
10^16
We'll use the one to one property and we'll
get:
x^2 = 10^16
x1 = +sqrt
10^16
x1 = +10^8
x2 =
-10^8
For log x^2 to exist, x>0, so
the equation will have only one solution, namely x =
+10^8
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