solve the equation: f(x) = x^2 - 3x + 4

f(x) = x^2 - 3x + 4

Let us
use the fomula to solve:

we note that
:

delta = b^2 - 4ac = -7 is
negative.

If delta < 0  , then the roots are complex
( not real).

Then we have complex
roots.

x= [-b + sqrt(b^2 -
4ac)]/2a

x1= [3 + sqrt(9 - 16)/2 = (3+ sqrt(-7) /2 = [3 +
(sqrt7)i]/2

x2= (3-
(sqrt7)*i]/2

Then , the solution
is:

 x= { 3/2 + (sqrt7/2)*i  ,  3/2 -
(sqrt7/2)*i }