Because the equations of the system are linear, we'll use
the matrix formed by the coefficients of the variables to calculate the determinant of
the system:
2
-3
det A
=
1 5
det
A = 10+3 = 13
det A = 13 different from
zero.
Now, we'll calculate
x:
x = det x/ det
A
-1
-3
det x
=
7 5
det
x = -5 - 21 = -26
x =
-26/13
x =
-2
Now, we'll calculate
y:
2
-1
det y
=
1 7
det
y = 14-1
det y
=15
y = det y/ det
A
y = 15/13
y =
15/13
The solution of the
system is: {(-2 , 15/13)}
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